Count Negative Numbers in a Row And Column Wise Sorted Matrix [Amazon]
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The given Matrix satisfies the following properties :
M [ i ] [ j ] ≤ M [ i ] [ j + 1 ] // Column wise sorted
M [ i ] [ j ] ≤ M [ i + 1 ] [ j ] // Row wise sorted
For example :
-3 | -2 | -1 | 1 |
-2 | -12 | 3 | 4 |
4 | 5 | 7 | 8 |
Naive Solution :
- Traverse the matrix from left -> right, top -> bottom order
- Count the number of negative elements
- Hence, O(n^2) complexity
Optimal Solution :
- Traverse the matrix from right-> left, top -> bottom.
- Find the last negative number’s index in the 1st row.
- Using this information, find the last negative number’s index in the 2nd row.
- Keep repeating this process until either you run out of negative numbers or you get to the last row.
Watch the following video to see this algorithm in action !
Let us know if you would like to know more about matrix problems, by leaving your comments !
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